三年級數(shù)學練習

三年級數(shù)學練習11476

26,bookchizhepaperwillwork,artchizhetechnologywill

yield-PuSongling

Mathexercisesforgradethree

Fullname

Fillintheblanks(22+6)

The248/3(two)digitistaking

645/2'smosthigh(100)isa

Analysis:thefirstdivisionofthedividend248is2,divided

by3isnotenough,sothequotientistwodigits;theaesthetic

pointofviewexcept645,thefirstis6,dividedby2,enough

todivide,thethreefiguresofbusiness,thehighestnumber

ofthreedigitsis100

Xiaolanwas10yearsoldinAugust.Hewasbornin(1999),in

thefirstquarteroftheyear(90)

Analysis:thisyearis2009,2009-10=19991999yearisaleap

year,thefirstquarterofMarch,oneortwodaysofthe31,

28,31,90days

ThehouseholdsinMaytheaveragedailyelectricityconsumption

4degrees,thefamilyinMayatotalofelectricity(124).

Analysis:Mayislarge,thereare31days,theaveragedaily

electricity4degrees,31daysis31to4degrees,sothetotal

is124degrees

Xiaomingwith4smallcubesalsorideoutthefollowing

three-dimensionalgraphics

ABCD

Fromthefrontview,yes,thegraphis(B)

Thesamepatternthatisseenfromthesideis(A,C,D)

(3)thesolidfigureseenfromaboveis(A)

Analysis:thekeytothisproblemistofindtherightdirection

toobserve,thedirectionmustbedetermined

Bein,fillinthe,〃<"or〃=〃

43x24x18x3979*11*23*68

76x12x12x7622x15x22*3*4

Analysis:twoX24multiplier43respectivelytwomultiplier

18*39,productiscertainlylarge,soin79*11>;product

ismorethan800,23*68oftheproductismorethan1400,so

fillin<x12and12x76;76timesthesame,justswapped.

Accordingtoits,onbothsidesofthemultiplierinvariant

propertiesofproductexchangeposition,22*15=fi11;can

bewrittenin22*3*5,comparedwith22x3x4,twoofthe

samethirdmultiplier,themultiplier5isgreaterthan4,so

fill>(or22x3x4x1222canbewrittenas22,*15and

22*12comparedtooneanotherbythesamemultiplier,the

number15isgreaterthan12,sofill>)

XiaoMing'smotherwenttoBeijingonbusinessinMay14thand

returnedinJuly25th.Shewasonabusinesstrip(73)days

Analysis:May14th,-5,31,18days(31-14+1),June,30days,

July1st,-7,25,25days(25-1+1),18+30+25=73

Onesmalleast4minutesskipping356,Amanda3minutesskipping

291,twoofthem(Amanda)jumpfaster

Analysis:thesmallEastperminutejumpmorethan80,Amanda

perminutejumpmorethan90,soAmandajumpfaster

Ifyoucantexpecttousethemethodofestimation,youcan

workoutthespecificdatadirectly

Theyare,everyone,sbirthdayisthedayofthemonth?

XiaoJun:mybirthdayisover,andthenIgotoLaborDay(April

30th)

Analysis:LaborDayisMay1st,theendofLaborDayistheday

beforelaborday,soitisApril30th

XiaoLi:mybirthdayis3daysbeforetheNationalDay

(September28th)

Analysis:theNationalDayisOctober1st,thedaybefore

September30th,thefirsttwodaysinSeptember29th,thefirst

threedaysinSeptember28th

Xiaoyan:mybirthdayisthelastdayoftheyear

(December31st)

Analysis:thelastdayoftheyearisDecember31st

XiaoMing:mybirthdayistwodayslaterthanchildren'sDay

(June3rd)

Analysis:Children'sDayisJune1st,theeveningisJune2nd,

andthetwodayisJune3rd

Inthefollowing,()fillin"translation"or"rotation”

(1)XiaoHongisswingingontheswingsinthepark

(2)XiaoLiMacolabottlecapis(spin)

(3)Mompullsdraweris(translation)

(4)theantennathatpullstheradiois(Pan)

Analysis:thinkinthemindofsuchanaction,andthendraw

aconclusionbasedonthefeaturesoftranslationandrotation

Ihave2,4,6,8,fourfigureswerefilledinto-written,

multiplicationformula

Howshouldtheproducttofillthefortieth*-

Analysis:toaccumulatetothemaximum,thenumberontheten,

8and6respectivelyinthetenandtwomultiplier,tosomemore

than80,totwothenumberofremaininginthelargerofthe

4and6combinedwiththecompositionof64,thelastremaining

2and8thecombinationof82,itis6482,thevolumeratio

of62to84,evenifyoudonotbelievea

Howshouldtheminimumproducttofill--X--

Analysis:toputtheminimumproduct,smallnumberontheten,

2and4respectivelyinthetenandtwomultiplier,howtoput

anumberonthecontrarywillbeaproblem,becausefewmore

than40,sothesmallnumberoftwooftheremaining6andthe

consistencyofthe2,consistingof26,8and4,consistingof

48,thisis2648,itsvolumeratio28to46

Two,todeterminetheproblem(totick"wrong'X"5points)

1multipliedbyanynumber,0,0dividedbyanynumberwillalso

be0

Analysis:itiswrong,“0multipliedbyanynumberis0"is

correct,“0dividedbyanynumberalsoget0'iswrong,because

“0dividedbyanyisnot0ofthenumberis0'isright

Attheendof2.460,the4operatorshavea0

Analysis:iswrong,thereisnobusinessattheendof0tosee

thedividendattheendof0infrontofthenumberisdivisible,

iftheremaindershall,incombinationwith0tocalculate,the

calculationtotheten,tenmorethan2,combinedwitha0into

20andcontinuingtocalculate,abusiness5business0

Attheendofthe3.40*50,thereareonlytwo0

Analysis:wrong,4multipliedby5,20,plus2attheendof

0,3shouldbe0

Theproductof4.36x2x4isequaltotheproductof36*8

Analysis:Yes,because36x2x4canbewrittenas36*8

5.1989yearsisadaylessthan1900

Asto...

Analysis:itiswrong,thetwoyearisaleapyear,is365days

Although1900canbedivisibleby4,itisahundredyears,

Soitdependsonwhetheritcanbedividedby400todetermine

whetheritisaleapyearornot

Three、chooseonlyonecorrectanswerforeachquestion

(5points)

1,3swallows,4pests,600swallows,1swallows,4dayseating

pests

50,200,150

Analysis:ask1swallows,4daystoeatpests,howmany,you

havetoaverage600insectsto3swallows,600dividedby3,

200,sochoose2

2,2and2004areleapyears,andthelatterleapyearis()

2000,2008,2010,2012

Analysis:2004isaleapyear,fouryearsaleap,leapyearand

leapyear,separatedbythreeyears,2004+4=2008,soit，sthe

nextleapyearis2008,choose2

3,from8a.m.to4p.m.,MasterWangprocessed320parts,with

anaveragemachiningperhour

1280,40,80

Analysis:from8a.m.to4p.m.,after8hours,320partswere

completedin8hours,sotheaverageallocationwas8hours,

and320dividedby8was40

4,423/tomakethebusinessistwodigits,"-"canfill

0

Anumberlessthan4=onedigitgreaterthan4.4

Analysis:tomakethebusinessistwofigures,thefirstmust

notbeenough,exceptthenumberintheboxmustbelargerthan

the4,sochoose2

The5andtwodigitnumbersofthetwodigitnumbersare()

Threedigits,fourdigits,threedigitsorfourdigits

Analysis:becausetheproductmaybethreefigures,theremay

befourfigures,selectionandIIarenotcomprehensive,and

eachquestionhasonlyonecorrectanswer,sochoose

Four.Calculationquestions

(25points)

1,writetheanswerdirectly

5points

80x40=0/2=400/8=460/2=240/6=8.

8557=45x20==0*78=(3643)/6=60...5...

2,youshouldmaketheverticalcalculation,checking

(20points,with4pointsforeachitem,and3fortheremainder)

68*72=50*32=/712/6=

197/4=/546/38*23=6=

Analysis:carefulcalculation,carefulinspection

Five,operationproblems

(6points

1,move,move,willmovetotheright6lattices,figure2

downwardtranslation5lattices,thediagramupwardmoves4

lattices

Analysis:lookatthedirectionofthetranslationand

translationofthenumberofsquares,findeachcorresponding

pointshouldbeintheposition,andpoint,andthendraw,the

keyistoindicatethedirectionofmovementofthearrowcan

notbeless

Six,problemsolving(25+6points)

One

Threegrade4studentsparticipateinropeskippingcompetition,

atotalof120people

Ifthenumberofclassesisequal,eachclassisdividedinto

2groups.Howmanypeoplearethereineachgroup?

Analysis:thefirstmethodtocalculatetheaveragenumberof

peopleineachgroup,weneedtoknowthenumberofclassesand

thenumberofpointstothegroupnumberis2,butthatnumber

ofstudentsdonotknow,wemustfirstcalculatetheclass

numberthroughtheconditionsofthetwoclassesof4and120

“theclassnumberknow,canaverage2groups,theaveragenumber

ofpeopleineachgroup.

120/4=30(person)

30/2-15(person)

Answer:anaverageof12peoplepergroup

Method2:because120peoplefinallywanttobesharedintoeach

group,soyoucanfirstfindouthowmanygroupsareinthewhole

class,andthenaskfortheaveragenumberofpeopleineach

group

4x2=8(Group)

120/8=15(person)

Answer:anaverageof12peoplepergroup

2.,theschoolbought8boxesofbooks,eachboxof80copies,

theaverageto5classes,eachclasscansharehowmuch?

Analysis:eachclasscandecidehowmuchofthis,mustknowhow

muchofthis,accordingtothe"8box"and"80perbox“canbe

obtainedbythetotalnumberofthetotalnumber,thiscameout,

andthentheaverageof5classes,eachclasscanbecalculated

todecidehowmuchofthis.

80x8=640(Ben)

640/5=128(this)

Answer:eachclasscanget128copies

3,agarmentfactoryfromApril28thtoMay2nd,atotalof370

piecesofclothingprocessing,theaveragenumberofpiecesof

clothingperday?

Theaveragedailyprocessingrequirementsanalysis:howmany

piecesofclothing,clothingprocessingdaysneedtoknowthe

totalnumberandthetotalnumberofprocessing,is370,the

numberofdaysrequiredprocessingisgoodafterthe

calculation,youcanput370piecesofclothingtothesedays

onaverage

April28th-430,3days

May1st-52,2days

3+2=5(day)

370/5=74(pieces)

Answer:74piecesofclothingareprocessedonaverageeveryday

4,theexperimentalprimaryschoolstudentsgoouting,2buses

cansit92people

Accordingtothiscalculation,thereare937peopleintheir

school,21largebuses,enoughseats?

Analysis:wanttoknowenoughtosit,thenumberofseatsby

carandbusnumbertocompare,thenumberis937,thenumber

ofseatsnotdirectlygiven,shoulduseeverycarseatnumber

bythenumberofvehiclesis21,thenumberofvehicles,the

numberofseatspercarnotdirectlygiven,onlyknowthat2

cars92peoplecansit,itmustfirstcalculatehowmanypeople

cansit1cars,andthenstepbysteptosolve

92/2-46(person)

46x21=966(person)

966>937

Answer:enoughtosit

5,ZhangShushutoprocess560parts,hebeganinAugust28th,

processing90partsperday,bySeptember2ndcancompletethe

task?

Analysis:toknowinSeptember2ndtocompletethetask,will

need-9monthAugust28thprocessingquantityandnumber2days

thistimeinprocessingwerecomparedineveryknownprocess

90,thespecificnumberofdaystofirstcalculate,andthen

processedtocalculatethenumberofthisperiodoftimeand

thencompare

(or,aftercountingthedays,seehowmanypartsareneededper

dayfor560partstobecompletedinsomanydays,

Andthencomparetheactualnumberofprocessingperday

)

August28th-831,4days

September1st-92,2days

4+2=6(day)

90x6=540(a)

540<560

Answer:bySeptember2ndcannotcomplete