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1、 Figure 3. Figure 3a presents the circuit that supplies the sample, including the sample P, a milliammeter mA, to measure the current i through the sample, a millivoltmeter mV, to measure the Hall voltage (using the compensation method we obtain a more accurate measure of UH, the source S1, the pote

2、ntiometer R1, and the switch K1. Figure 3b presents the electromagnet circuit, including the electromagnet coil C, the ammeter A to measure the current I through the electromagnet, the potentiometer R2, the source S2, and the switch K2. 4. Working procedure: 1. Connect the sources S1 and S2 by plugg

3、ing them and turning on the switches K1 and K2. Using the potentiometer R1 a constant current i through the sample is fixed. The values of the current i for which the measurements have to be performed are indicated on the desk. 2. Using the potentiometer R2, vary the current I through the electromag

4、net coil from 0.2 A to the maximum value of 3A. 3. For each value of I, read U H using the millivoltmeter mV. 4. Repeat the measurements for different values of the current i through the sample. The results will be written in Table 1, which contains the values of the induction B for different values

5、 of the current I through the coil. The sample sizes a, b, c, are given on the desk. The current density j is: j= i . ab 171 (26 Table 1 UH (V I (A 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 2.8 3.0 i (mA j (A/m2 B (T 0.016 0.040 0.068 0.098 0.128 0.156 0.170 0.180 0.190 0.196 0.202 0.2

6、08 0.213 0.218 0.222 0.225 . . 5. Draw the electromagnet calibration curve B = B( I , in order to find the values of B for the coil current values different from those in Table 1. As when the current is flowing through both sample and coil these devices can go out of order, turn on the switches K1 a

7、nd K2 only when we read the data. 5. Experimental data processing 1. Using the data from Table 1, plot on millimetric paper the dependencies U H = U H ( B for j = const. Due to the non-linearity of the Hall effect and the sample heating during the measurements, we will not obtain straight lines; the

8、 tangents to the curves at the origin (B = 0 will have the slopes: mk = aRH jk , k = 1, 2, ., N . (27 With the slopes m1 , m2 , . mN , obtained from the graphs, compute the values of the corresponding Hall constants: 172 (k RH = mk . ajk N (28 Compute the mean Hall constant: RH = 1 N (k . RH (29 k =

9、1 The value of the Hall constant will be given in the form: RH = RH ± RH , (30 where RH represents the mean square deviation of the mean Hall constant, which is computed with the formula: RH = N 1 (k RH RH N ( N 1 k =1 ( 2 . (31 2. Knowing the values of the Hall constant, the mean charge carrie

10、r (hole concentration for the sample is determined using the relation (21: p = 1 RH e . (32 The Hall mobility is determined from the relations (22, (24. The errors for p and µ H are computed taking into account that the other constants are supposed exact, so that the relative errors for p, µ H and RH are equal. When processing the experimental data

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